KCET · Chemistry · Amines
An alkyl halide reacts with alcoholic ammonia in a sealed tube, the product formed will be
- A a primary amine
- B a secondary amine
- C a tertiary amine
- D a mixture of all the three
Answer & Solution
Correct Answer
(D) a mixture of all the three
Step-by-step Solution
Detailed explanation
When an alkyl halide reacts with alcoholic ammonia in a sealed tube then a mixture of primary, secondary and tertiary amine is formed
\(R \mathrm{X}+\mathrm{NH}_{3} \longrightarrow R \mathrm{NH}_{2}+\mathrm{H} X\)
pri-amine
\(\mathrm{RNH}_{2}+X R \longrightarrow R_{2} \mathrm{NH}+\mathrm{H} X\)
\(R_{2} \mathrm{NH}+X R \longrightarrow R_{3} \mathrm{~N}+\mathrm{H} X\)
\(R \mathrm{X}+\mathrm{NH}_{3} \longrightarrow R \mathrm{NH}_{2}+\mathrm{H} X\)
pri-amine
\(\mathrm{RNH}_{2}+X R \longrightarrow R_{2} \mathrm{NH}+\mathrm{H} X\)
\(R_{2} \mathrm{NH}+X R \longrightarrow R_{3} \mathrm{~N}+\mathrm{H} X\)
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