KCET · Chemistry · Electrochemistry
The conductivity of centimolar solution of KCl at \(298\) K is \(0.021\text{ Ohm}^{-1}\text{cm}^{-1}\) and the resistance of the cell containing the solution at \(298\) K is \(60\,\Omega\). The value of cell constant (\(G^*\)) is __________.
- A \(3.28\text{ cm}^{-1}\)
- B \(1.26\text{ cm}^{-1}\)
- C \(3.34\text{ cm}^{-1}\)
- D \(1.34\text{ cm}^{-1}\)
Answer & Solution
Correct Answer
(B) \(1.26\text{ cm}^{-1}\)
Step-by-step Solution
Detailed explanation
The relationship between conductivity (\(\kappa\)), resistance (\(R\)), and cell constant (\(G^*\)) is given by:
\(G^* = \kappa \times R\)
Substituting the given values:
\(\kappa = 0.021 \text{ Ohm}^{-1}\text{cm}^{-1}\)
\(R = 60 \, \Omega\)
\(G^* = 0.021 \times 60 = 1.26 \text{ cm}^{-1}\)
Answer: \(1.26\text{ cm}^{-1}\)
\(G^* = \kappa \times R\)
Substituting the given values:
\(\kappa = 0.021 \text{ Ohm}^{-1}\text{cm}^{-1}\)
\(R = 60 \, \Omega\)
\(G^* = 0.021 \times 60 = 1.26 \text{ cm}^{-1}\)
Answer: \(1.26\text{ cm}^{-1}\)
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