KCET · BIOLOGY · STD 12 - 4. Principles of Inheritance and Variation
In garden pea, round shape of seeds is dominant over wrinkled shape. A pea plant heterozygous for round shape of seed is selfed and 1600 seeds produced during the cross are subsequently germinated. How many seedlings would have the parental phenotype?
- A 400
- B 1600
- C 1200
- D 800
Answer & Solution
Correct Answer
(C) 1200
Step-by-step Solution
Detailed explanation
(C) 1200,
If the pea plant is heterozygous for round shape then its genotype would be Rr.
Parents : \(Rr \times Rr\)
\(\quad\)\(\quad\)↓ (selfing)
Progeny: RR Rr Rr rr
Phenotypically, the ratio will be \(3: 1\) i.e., only rr seedlings will show wrinkled phenotype, rest will show round shape.
\(1200 \rightarrow\) Round shape (RR, Rr)
\(400 \rightarrow\) Wrinkled (r)
If the pea plant is heterozygous for round shape then its genotype would be Rr.
Parents : \(Rr \times Rr\)
\(\quad\)\(\quad\)↓ (selfing)
Progeny: RR Rr Rr rr
Phenotypically, the ratio will be \(3: 1\) i.e., only rr seedlings will show wrinkled phenotype, rest will show round shape.
\(1200 \rightarrow\) Round shape (RR, Rr)
\(400 \rightarrow\) Wrinkled (r)
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