KCET · Physics · Waves and Sound
A stationary point source of sound emits sound uniformly in all directions in a non-absorbing medium. Two points \(P\) and \(Q\) are at a distance of \(4 \mathrm{~m}\) and \(9 \mathrm{~m}\) respectively from the source. The ratio of amplitudes of the waves at \(P\) and \(Q\) is
- A \(\frac{3}{2}\)
- B \(\frac{4}{9}\)
- C \(\frac{2}{3}\)
- D \(\frac{9}{4}\)
Answer & Solution
Correct Answer
(D) \(\frac{9}{4}\)
Step-by-step Solution
Detailed explanation

For an isotropic point source of power P, intensity I at a distance \(\mathrm{r}\) from it is
\(\mathrm{I}=\frac{\mathrm{P}}{4 \pi \mathrm{r}^{2}}\)
Since power P remains the same,
\(\therefore \frac{\mathrm{I}_{1}}{\mathrm{I}_{2}}=\left(\frac{\mathrm{r}_{2}}{\mathrm{r}_{1}}\right)^{2}=\left(\frac{9}{4}\right)^{2}\)
\(\because I \propto \mathrm{A}^{2}\)
where \(A\) is the amplitude of a wave \(\therefore \frac{\mathrm{A}_{1}}{\mathrm{~A}_{2}}=\sqrt{\frac{\mathrm{I}_{1}}{\mathrm{I}_{2}}}=\frac{9}{4}\)
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