ExamBro
ExamBro
JEE Mains · Maths · STD 12 - 1. relation and function

Let \(D\) be the domain of the function \(f(x)=\sin ^{-1}\) \(\left(\log _{3 x}\left(\frac{6+2 \log _3 x}{-5 x}\right)\right)\). If the range of the function \(g: D \rightarrow R\) defined by \(g( x )= x -[ x ],([ x ]\) is the greatest integer function), is ( \(\alpha, \beta)\), then \(\alpha^2+\frac{5}{\beta}\) is equal to

  1. A \(46\)
  2. B \(135\)
  3. C \(136\)
  4. D \(45\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(135\)

Step-by-step Solution

Detailed explanation

\(\frac{6+2 \log _3 x}{-5 x} > 0\) and \(x > 0\) and \(x \neq \frac{1}{3}\) \(\text { this gives } x \in\left(0, \frac{1}{27}\right) \ldots \text { (1) }\) \(-1 \leq \log _{3 x}\left(\frac{6+2 \log _3 x}{-5 x}\right) \leq 1\)…