JEE Mains · Maths · STD 12 - 1. relation and function
Let \(D\) be the domain of the function \(f(x)=\sin ^{-1}\) \(\left(\log _{3 x}\left(\frac{6+2 \log _3 x}{-5 x}\right)\right)\). If the range of the function \(g: D \rightarrow R\) defined by \(g( x )= x -[ x ],([ x ]\) is the greatest integer function), is ( \(\alpha, \beta)\), then \(\alpha^2+\frac{5}{\beta}\) is equal to
- A \(46\)
- B \(135\)
- C \(136\)
- D \(45\)
Answer & Solution
Correct Answer
(B) \(135\)
Step-by-step Solution
Detailed explanation
\(\frac{6+2 \log _3 x}{-5 x} > 0\) and \(x > 0\) and \(x \neq \frac{1}{3}\) \(\text { this gives } x \in\left(0, \frac{1}{27}\right) \ldots \text { (1) }\) \(-1 \leq \log _{3 x}\left(\frac{6+2 \log _3 x}{-5 x}\right) \leq 1\)…
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