ExamBro
ExamBro
JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism

A closely wounded circular coil of radius \(5\,cm\) produces a magnetic field of \(37.68 \times 10^{-4}\,T\) at its center. The current through the coil is \(......A\). [Given, number of turns in the coil is \(100\) and \(\pi=3.14]\)

  1. A \(3\)
  2. B \(6\)
  3. C \(9\)
  4. D \(12\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(3\)

Step-by-step Solution

Detailed explanation

\(B _{\text {centre}}=\frac{N \mu_{0} I}{2 R }\) \(37.68 \times 10^{-4}=\frac{100 \times 4 \pi \times 10^{-7} \times I }{2 \times 5 \times 10^{-2}}\) \(I =3\,A\)
Same subject
Explore more questions on app