JEE Mains · Maths · STD 12 - 9. differential equations
Let \(\mathrm{F}:[3,5] \rightarrow \mathrm{R}\) be a twice differentiable function on \((3,5)\) such that \(\mathrm{F}(\mathrm{x})=\mathrm{e}^{-\mathrm{x}}\) \(\int_{3}^{x}\left(3 t^{2}+2 t+4 F^{\prime}(t)\right) \,d t\) If \(F^{\prime}(4)=\frac{\alpha e^{\beta}-224}{\left(e^{\beta}-4\right)^{2}}\), then \(\alpha+\beta\) is equal to \(....\)
- A \(8\)
- B \(16\)
- C \(48\)
- D \(32\)
Answer & Solution
Correct Answer
(B) \(16\)
Step-by-step Solution
Detailed explanation
\(F(3)=0\) \(\mathrm{e}^{\mathrm{x}} \mathrm{F}(\mathrm{x})=\int_{3}^{\mathrm{x}}\left(3 \mathrm{t}^{2}+2 \mathrm{t}+4 \mathrm{~F}^{\prime}(\mathrm{t})\right) \,\mathrm{dt}\) \(e^{x} F(x)=e^{x} F^{\prime}(x)=3 x^{2}+2 x+4 F^{\prime}(x)\)…
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