JEE Mains · Physics · STD 11 - 14. waves and sound
Two open organ pipes of length \(60 \mathrm{~cm}\) and \(90 \mathrm{~cm}\) resonate at \(6^{\text {th }}\) and \(5^{\text {th }}\) harmonics respectively. The difference of frequencies for the given modes is _______ \(\mathrm{Hz}\). (Velocity of sound in air \(=333 \mathrm{~m} / \mathrm{s}\) )
- A \(740\)
- B \(730\)
- C \(720\)
- D \(710\)
Answer & Solution
Correct Answer
(A) \(740\)
Step-by-step Solution
Detailed explanation
The difference in frequency in open organ pipe \(=\) \(\mathrm{f}=\frac{\mathrm{nv}}{2 \mathrm{~L}}\) \(\Delta \mathrm{f}=\frac{6 \mathrm{v}}{2 \times 0.6}-\frac{5 \mathrm{v}}{2 \times 0.9}\) \(\mathrm{v}=333 \mathrm{~m} / \mathrm{s}\) \(\Delta \mathrm{f}=740 \mathrm{~Hz}\)
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