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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2024
  • Easy
  • Numerical

Two open organ pipes of length \(60 \mathrm{~cm}\) and \(90 \mathrm{~cm}\) resonate at \(6^{\text {th }}\) and \(5^{\text {th }}\) harmonics respectively. The difference of frequencies for the given modes is _______ \(\mathrm{Hz}\). (Velocity of sound in air \(=333 \mathrm{~m} / \mathrm{s}\) )

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Answer & Solution

Correct Answer

(A) \(740\)

Step-by-step Solution

Detailed explanation

The difference in frequency in open organ pipe \(=\)

\(\mathrm{f}=\frac{\mathrm{nv}}{2 \mathrm{~L}}\)

\(\Delta \mathrm{f}=\frac{6 \mathrm{v}}{2 \times 0.6}-\frac{5 \mathrm{v}}{2 \times 0.9}\)

\(\mathrm{v}=333 \mathrm{~m} / \mathrm{s}\)

\(\Delta \mathrm{f}=740 \mathrm{~Hz}\)

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