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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2019
  • Easy
  • Numerical

A musician using an open flute of length \(50\,cm\) produces second harmonic sound waves. A person runs towards the musician from another end of a hall at a speed of \(10 \,km/h.\) If the wave speed is \(330\,m/s,\) the frequency heard by the running person shall be close to...... \(Hz\)

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Answer & Solution

Correct Answer

(A) \(666\)

Step-by-step Solution

Detailed explanation

\(f=\frac{2}{2 \ell} V_{s}=\frac{330}{0.5}=660 \mathrm{Hz}\)

\( \therefore \quad f^{\prime}=f\left(\frac{v_{s}+v}{v_{s}}\right)=(660)\left(\frac{330+\frac{50}{18}}{330}\right)=660\left(1+\frac{50}{18 \times 330}\right)\)

\(=666 \mathrm{Hz}\)

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