JEE Mains · Physics · STD 12 - 1. Electric charges and fields
Two identical conducting spheres \(\mathrm{P}\) and \(\mathrm{S}\) with charge \(Q\) on each, repel each other with a force \(16 \mathrm{~N}\). A third identical uncharged conducting sphere \(\mathrm{R}\) is successively brought in contact with the two spheres. The new force of repulsion between \(\mathrm{P}\) and \(\mathrm{S}\) is what?
- A \(4 \mathrm{~N}\)
- B \(6 \mathrm{~N}\)
- C \(1 \mathrm{~N}\)
- D \(12 \mathrm{~N}\)
Answer & Solution
Correct Answer
(B) \(6 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
\(F_{P S} \propto Q^2\) \(F_{P S}=16 N\) Now If \(\mathrm{P} \& \mathrm{R}\) are brought in contact then Now If \(\mathrm{S} \& \mathrm{R}\) are brought in contact then New force between \(P \& S\) is :…
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