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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2018
  • Hard
  • MCQ

A plane polarized light is incident on a polariser with its pass axis making angle \(\theta\) with \(x-\) axis, as shown in the figure. At four different values of \(\theta\), \(\theta\, = 8^o, 38^o, 188^o\) and \(218^o\), the observed intensities are same. What is the angle between the direction of polarization and \(x-\) axis.....\(^o\)

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Answer & Solution

Correct Answer

(A) \(203\)

Step-by-step Solution

Detailed explanation

Let the angle between polarization direction and \(x\) -axis be \(\theta^{\prime}\)

So angle between polarisation direction and pass axis of polariser is \(\left(\theta^{\prime}-\theta\right)\)

Given \(\theta  = {8^o},{88^o},\,{188^o},\,\,{218^o}\)

\(\therefore I=I_{o} \cos ^{2}\,\left(\theta^{\prime}-\theta\right)\)

For \(\theta^{\prime}=203^o\) intensities are same

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