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JEE Mains · Physics · STD 12 - 10. Wave optics
A plane polarized light is incident on a polariser with its pass axis making angle \(\theta\) with \(x-\) axis, as shown in the figure. At four different values of \(\theta\), \(\theta\, = 8^o, 38^o, 188^o\) and \(218^o\), the observed intensities are same. What is the angle between the direction of polarization and \(x-\) axis.....\(^o\)
- A \(203\)
- B \(45\)
- C \(98\)
- D \(128\)
Answer & Solution
Correct Answer
(A) \(203\)
Step-by-step Solution
Detailed explanation
Let the angle between polarization direction and \(x\) -axis be \(\theta^{\prime}\) So angle between polarisation direction and pass axis of polariser is \(\left(\theta^{\prime}-\theta\right)\) Given \(\theta = {8^o},{88^o},\,{188^o},\,\,{218^o}\)…
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