Two charges each of magnitude \(0.01\,C\) and separated by a distance of \(0.4\,mm\) constitute an electric dipole. If the dipole is placed in an uniform electric field ' \(\vec{E}\) ' of \(10\,dyne/C\) making \(30^{\circ}\) angle with \(\overrightarrow{ E }\), the magnitude of torque acting on dipole is :

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Answer & Solution

Correct Answer

(B) \(2.0 \times 10^{-10}\,Nm\)

Detailed explanation

\(|\overrightarrow{ P }|= qd\)

\(=0.01 \times 0.4 \times 10^{-3}\)

\(=4 \times 10^{-6}\)

\(|\vec{\tau}|=\operatorname{PE} \sin \theta\)

\(=4 \times 10^{-6} \times 10 \times 10^{-5} \times \sin 30\)

\(=4 \times 10^{-6-5+1} \times \frac{1}{2}\)

\(=2 \times 10^{-10}\)

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