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JEE Mains · Physics · STD 12 - 3. current electricity

To find the resistance of a galvanometer by the half deflection method the following circuit is used with resistances \(R_1 = 9970\,\Omega,\) \(R_2 = 30\,\Omega\) and \(R_3 = 0\,\Omega.\) The deflection in the galvanometer is \(d\). With \(R_3 = 107\,\Omega\) the deflection changed to \(\frac {d}{2}\)The galvanometer resistance is approximately ............... \(\Omega\)

  1. A \(107\)
  2. B \(137\)
  3. C \(53.5\)
  4. D \(77\)
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(D) \(77\)

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