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JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement

Three students \(S_{1}, S_{2}\) and \(S_{3}\) perform an experiment for determining the acceleration due to gravity \((g)\) using a simple pendulum. They use different lengths of pendulum and record time for different number of oscillations. The observations are as shown in the table.
Student No. Length of pendulum \((cm)\) No. of oscillations \((n)\) Total time for oscillations Time period \((s)\)
\(1.\) \(64.0\) \(8\) \(128.0\) \(16.0\)
\(2.\) \(64.0\) \(4\) \(64.0\) \(16.0\)
\(3.\) \(20.0\) \(4\) \(36.0\) \(9.0\)
(Least count of length \(=0.1 \,{m}\), least count for time \(=0.1\, {s}\) ) If \(E_{1}, E_{2}\) and \(E_{3}\) are the percentage errors in \('g'\) for students \(1,2\) and \(3\) respectively, then the minimum percentage error is obtained by student no. ....... .

  1. A \(4\)
  2. B \(3\)
  3. C \(1\)
  4. D same in all
Verified Solution

Answer & Solution

Correct Answer

(C) \(1\)

Step-by-step Solution

Detailed explanation

\(T=2 \pi \sqrt{\frac{\ell}{g}} \Rightarrow g=\frac{4 \pi^{2} \ell}{T^{2}}\) \(\frac{\Delta g}{g}=\frac{\Delta \ell}{\ell}+\frac{2 \Delta T}{T}\) \(\Delta T=\frac{\text { least count of time }\left(\Delta T_{0}\right)}{\text { number of oscillations(n) }}\)…
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