JEE Mains · Maths · STD 11 - 9. straight line
Consider a triangle having vertices \(A(-2,3), B(1,9)\) and \(C(3,8)\). If a line \(L\) passing through the circum-center of triangle \(\mathrm{ABC}\), bisects line \(\mathrm{BC}\), and intersects \(\mathrm{y}\)-axis at point \(\left(0, \frac{\alpha}{2}\right)\), then the value of real number \(\alpha\) is \(.....\)
- A \(81\)
- B \(3\)
- C \(9\)
- D \(45\)
Answer & Solution
Correct Answer
(C) \(9\)
Step-by-step Solution
Detailed explanation
\((\sqrt{50})^{2}=(\sqrt{45})^{2}+(\sqrt{5})^{2}\) \(\angle \mathrm{B}=90^{\circ}\) \(\text { Circum-center }=\left(\frac{1}{2}, \frac{11}{2}\right)\) Mid point of \(B C=\left(2, \frac{17}{2}\right)\) Line…
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