JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
The workdone by a gas molecule in an isolated system is given by, \(W =\alpha \beta^{2} e ^{-\frac{ x ^{2}}{\alpha kT }},\) where \(x\) is the displacement, \(k\) is the Boltzmann constant and \(T\) is the temperature, \(\alpha\) and \(\beta\) are constants. Then the dimension of \(\beta\) will be
- A \(\left[ M L ^{2} T ^{-2}\right]\)
- B \(\left[ M L T ^{-2}\right]\)
- C \(\left[ M ^{2} L T ^{2}\right]\)
- D \(\left[ M ^{0} L T ^{0}\right]\)
Answer & Solution
Correct Answer
(B) \(\left[ M L T ^{-2}\right]\)
Step-by-step Solution
Detailed explanation
\(\frac{ x ^{2}}{\alpha kT } \rightarrow\) dimensionless \(\Rightarrow[\alpha]=\frac{\left[ x ^{2}\right]}{[ kT ]}=\frac{ L ^{2}}{ ML ^{2} T ^{-2}}= M ^{-1} T ^{2}\) Now \([ W ]=[\alpha][\beta]^{2}\)…
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