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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2021
  • Hard
  • MCQ

The workdone by a gas molecule in an isolated system is given by, \(W =\alpha \beta^{2} e ^{-\frac{ x ^{2}}{\alpha kT }},\) where \(x\) is the displacement, \(k\) is the Boltzmann constant and \(T\) is the temperature, \(\alpha\) and \(\beta\) are constants. Then the dimension of \(\beta\) will be

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Answer & Solution

Correct Answer

(B) \(\left[ M L T ^{-2}\right]\)

Step-by-step Solution

Detailed explanation

\(\frac{ x ^{2}}{\alpha kT } \rightarrow\) dimensionless

\(\Rightarrow[\alpha]=\frac{\left[ x ^{2}\right]}{[ kT ]}=\frac{ L ^{2}}{ ML ^{2} T ^{-2}}= M ^{-1} T ^{2}\)

Now \([ W ]=[\alpha][\beta]^{2}\)

\([\beta]=\sqrt{\frac{ ML ^{2} T ^{-2}}{ M ^{-1} T ^{2}}}= M ^{1} L ^{1} T ^{-2}\)

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