The current voltage relation of a diode is given by \(I=(e^{1000V/T} -1)mA\) where the applied voltage \(V\) is in volts and the temperature \(T\) is in degree kelvin. If a student makes an error measuring \(±0.01\ V\) while measuring the current of \(5\ mA\) at \(300\ K\), what will be the error in the value of current in \(mA?\)

Pick an option to check your answer.

Verified Solution

Answer & Solution

Correct Answer

(D) \(0.2\)

Step-by-step Solution

Detailed explanation

The current voltage relation of diode is

\(I=\left(e^{1000 V / T}-1\right) \mathrm{mA}(\text { given })\)

When, \(I=5 m A, e^{1000 V / T}=6 m A\)

Also, \(d I=\left(e^{1000\, v / T}\right) \times \frac{1000}{T}\)

(By exponential function)

\(=(6\, m A) \times \frac{1000}{300} \times(0.01)\)

\(=0.2\, \mathrm{mA}\)

Same subject

One side of an equilateral prism is painted by a transparent material of refractive index \(n_2\). The refractive index of prism is \(1.6\). The minimum value of \(n_2\) required for total internal reflection from painted face is _______.

JEE Mains 2026 Hard
The charged particle moving in a uniform magnetic field of \((3\hat{i} + 2\hat{j})\) T has an acceleration \(\left(4\hat{i} - \dfrac{x}{2}\hat{j}\right)\) m/s\(^2\). The value of \(x\) is __________.

JEE Mains 2026 Medium
A monoatomic gas of mass \(4.0\, u\) is kept in an insulated container. Container is moving with velocity \(30 \,m / s\). If container is suddenly stopped then change in temperature of the gas \(\left( R =\right.\) gas constant) is \(\frac{ x }{3 R } .\) Value of \(x\) is ..........

JEE Mains 2021 Hard
A vector in \(x-y\) plane makes an angle of \(30^{\circ}\) with \(y\)-axis The magnitude of \(y\)-component of vector is \(2 \sqrt{3}\). The magnitude of \(x\)-component of the vector will be

JEE Mains 2023 Medium
Two radioactive substances \(A\) and \(B\) have decay constants \(5\lambda \) and \(\lambda \) respectively. At \(t = 0\), a sample has the same number of the two nuclei. The time taken for the ratio of the number of nuclei to become \((\frac {1}{e})^2\) will be

JEE Mains 2019 Medium
Consider the \(LR\) circuit shown in the figure. If the switch \(S\) is closed at \(t = 0\) then the amount of charge that passes through the battery between \(t = 0\) and \(t = \frac{L}{R}\) is

JEE Mains 2019 Hard

Explore more questions on app

From JEE Mains

For a given transistor amplifier circuit in \(CE\) configuration \(V_{C C}=1 V , R_c=1 k \Omega, R_b=100 k \Omega\) and \(\beta=100\). Value of base current \(I_b\) is

JEE Mains 2023 Medium
Two vessels \(A\) and \(B\) are of the same size and are at same temperature. A contains \(1 \mathrm{~g}\) of hydrogen and \(B\) contains \(1 \mathrm{~g}\) of oxygen. \(\mathrm{P}_{\mathrm{A}}\) and \(\mathrm{P}_{\mathrm{B}}\) are the pressures of the gases in \(A\) and \(\mathrm{B}\) respectively, then \(\frac{\mathrm{P}_{\mathrm{A}}}{\mathrm{P}_{\mathrm{B}}}\) is _______.

JEE Mains 2024 Hard
A body is performing simple harmonic with an amplitude of \(10 \,cm\). The velocity of the body was tripled by air Jet when it is at \(5 \,cm\) from its mean position. The new amplitude of vibration is \(\sqrt{ x } \,cm\). The value of \(x\) is________

JEE Mains 2022 Hard
The density of a solid metal sphere is determined by measuring its mass and its diameter. The maximum error in the density of the sphere is \(\left(\frac{x}{100}\right) \% .\) If the relative errors in measuring the mass and the diameter are \(6.0 \%\) and \(1.5 \%\) respectively, the value of \(x\) is

JEE Mains 2020 Hard
The torque of a force \(5 \hat{i}+3 \hat{j}-7 \hat{k}\) about the origin is \(\tau\). If the force acts on a particle whose position vector is \(2 \hat{i}+2 \hat{j}+\hat{k}\), then the value of \(\tau\) will be.

JEE Mains 2022 Easy
As shown in figure, a cuboid lies in a region with electric field \(E=2 x^2 \hat{i}-4 y \hat{j}+6 \hat{k} \quad N / C\). The magnitude of charge within the cuboid is \(n \varepsilon_0 C\). The value of \(n\) is \(............\) (if dimension of cuboid is \(1 \times 2 \times 3 \;m ^3\) )

JEE Mains 2023 Medium

Explore more questions on app