JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
The current voltage relation of a diode is given by \(I=(e^{1000V/T} -1)mA\) where the applied voltage \(V\) is in volts and the temperature \(T\) is in degree kelvin. If a student makes an error measuring \(±0.01\ V\) while measuring the current of \(5\ mA\) at \(300\ K\), what will be the error in the value of current in \(mA?\)
- A \(0.02\)
- B \(0.5\)
- C \(0.05\)
- D \(0.2\)
Answer & Solution
Correct Answer
(D) \(0.2\)
Step-by-step Solution
Detailed explanation
The current voltage relation of diode is \(I=\left(e^{1000 V / T}-1\right) \mathrm{mA}(\text { given })\) When, \(I=5 m A, e^{1000 V / T}=6 m A\) Also, \(d I=\left(e^{1000\, v / T}\right) \times \frac{1000}{T}\) (By exponential function)…
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