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JEE Mains · Maths · STD 11 - 6. permutation and combination
The number of ways in which \(5\) boys and \(3\) girls can be seated on a round table if a particular boy \(B_1\) and a particular girl \(G_1\) never sit adjacent to each other, is
- A \(5\times6!\)
- B \(6\times6!\)
- C \(7!\)
- D \(5\times7!\)
Answer & Solution
Correct Answer
(A) \(5\times6!\)
Step-by-step Solution
Detailed explanation
\(4\) boys and \(2\) girls in circle \(\Rightarrow \) \(5! \times \frac{{6!}}{{4!2!}} \times 2!\) \(\Rightarrow \) \(5\times6!\)
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