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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2021
  • Medium
  • MCQ

Region \(I\) and \(II\) are separated by a spherical surface of radius \(25\, {cm}\). An object is kept in region \(I\) at a distance of \(40\, {cm}\) from the surface. The distance of the image from the surface is \(.....\,cm\)

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Answer & Solution

Correct Answer

(C) \(37.58\)

Step-by-step Solution

Detailed explanation

\(\frac{\mu_{2}}{v}-\frac{\mu_{1}}{u}=\frac{\mu_{2}-\mu_{1}}{R}\)

\(\frac{1.4}{v}-\frac{1.25}{-40}=\frac{1.4-1.25}{-25}\)

\(\frac{1.4}{v}=-\frac{0.15}{25}-\frac{1.25}{40}\)

\(v=-37.58\, {cm}\)

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