JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
The angular speed of truck wheel is increased from \(900\, rpm\) to \(2460\, rpm\) in \(26\) seconds. The number of revolutions by the truck engine during this time is (Assuming the acceleration to be uniform).
- A \(1456\)
- B \(728\)
- C \(810\)
- D \(368\)
Answer & Solution
Correct Answer
(B) \(728\)
Step-by-step Solution
Detailed explanation
We know, \(\theta=\left(\frac{\omega_{1}+\omega_{2}}{2}\right)\) t Let number of revolutions be \(N\) \(\therefore 2 \pi N =2 \pi\left(\frac{900+2460}{60 \times 2}\right) \times 26\) \(N =728\)
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