ExamBro
ExamBro
JEE Mains · Physics · STD 11 - System of particles and rotational motion
  • JEE Mains 2021
  • Medium
  • Numerical

The angular speed of truck wheel is increased from \(900\, rpm\) to \(2460\, rpm\) in \(26\) seconds. The number of revolutions by the truck engine during this time is (Assuming the acceleration to be uniform).

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(728\)

Step-by-step Solution

Detailed explanation

We know, \(\theta=\left(\frac{\omega_{1}+\omega_{2}}{2}\right)\) t

Let number of revolutions be \(N\)

\(\therefore 2 \pi N =2 \pi\left(\frac{900+2460}{60 \times 2}\right) \times 26\)

\(N =728\)

Same subject
Explore more questions on app