JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2021
- Medium
- Numerical
The angular speed of truck wheel is increased from \(900\, rpm\) to \(2460\, rpm\) in \(26\) seconds. The number of revolutions by the truck engine during this time is (Assuming the acceleration to be uniform).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(728\)
Step-by-step Solution
Detailed explanation
We know, \(\theta=\left(\frac{\omega_{1}+\omega_{2}}{2}\right)\) t
Let number of revolutions be \(N\)
\(\therefore 2 \pi N =2 \pi\left(\frac{900+2460}{60 \times 2}\right) \times 26\)
\(N =728\)
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