JEE Mains · Maths · STD 12 - 6. Application of derivatives
The minimum area of a triangle formed by any tangent to the ellipse \(\frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{{81}} = 1\) and the co-ordinate axes is
- A \(12\)
- B \(18\)
- C \(26\)
- D \(36\)
Answer & Solution
Correct Answer
(D) \(36\)
Step-by-step Solution
Detailed explanation
Let \((h, k)\) be the point on ellipse through which tangent is passing. Equation of tangent at \((h, k)=\frac{x h}{16}+\frac{y k}{81}=1\) at \(y=0, x=\frac{16}{h}\) at \(x=0, y=\frac{81}{k}\) Area of…
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