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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
Equation of the line passing through the points of intersection of the parabola \(x^2 = 8y\) and the ellipse \(\frac{{{x^2}}}{3} + {y^2} = 1\) is
- A \(y- 3=0\)
- B \(y+ 3=0\)
- C \(3y + 1 =0\)
- D \(3y -1 =0\)
Answer & Solution
Correct Answer
(D) \(3y -1 =0\)
Step-by-step Solution
Detailed explanation
\({x^2} = 8y\,\,\,\,\,\,\,\,\,......\left( i \right)\) \(\frac{{{x^2}}}{3} + {y^2} = 1\,\,\,\,\,\,\,\,.....\left( {ii} \right)\) From \((i)\) and \((ii)\), \(\frac{{8y}}{3} + {y^2} = 1\,\,\,\,\, \Rightarrow y = - 3,\frac{1}{3}\) When \(y = - 3\), then \({x^2} = - 24\), which is…
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