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JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion

A boy pushes a box of mass \(2\, kg\) with a force \(\overrightarrow{ F }=(20 \hat{ i }+10 \hat{ j }) N\) on a frictionless surface. If the box was initially at rest, then ...........  \(m\) is displacement along the \(x-\)axis after \(10\, s\).

  1. A \(400\)
  2. B \(500\)
  3. C \(800\)
  4. D \(1200\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(500\)

Step-by-step Solution

Detailed explanation

\(\overrightarrow{ F }=20 \hat{ i }+10 \hat{ j }\) \(\overrightarrow{ a }=\frac{\overrightarrow{ F }}{ m }=\frac{20 \hat{ i }+10 \hat{ j }}{2} \Rightarrow 10 \hat{ i }+5 \hat{ j }\)…
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