Let \(\sigma\) be the uniform surface charge density of two infinite thin plane sheets shown in figure. Then the electric fields in three different region \(E_{ I }, E_{ II }\) and \(E_{III}\) are

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Correct Answer

(D) \(\vec{E}_{ I }=-\frac{\sigma}{\epsilon_0} \hat{n}, \vec{E}_{\text {II }}=0, \vec{E}_{\text {III }}=\frac{\sigma}{\epsilon_0} \hat{n}\)

Step-by-step Solution

Detailed explanation

Assuming RHS to be \(\hat{n}\)

\(\vec{E}_{ I }=\frac{\sigma}{2 \epsilon_0}(-\hat{n})+\frac{\sigma}{2 \epsilon_0}(-\hat{n})=-\frac{\sigma}{\epsilon_0} \hat{n}\)

\(\vec{E}_{I I}=0\),

\(\vec{E}_{I I I}=\frac{\sigma}{2 \epsilon_0}(\hat{n})+\frac{\sigma}{2 \epsilon_0}(\hat{n})=\frac{\sigma}{\epsilon_0}(\hat{n})\)

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