JEE Mains · Physics · STD 12 - 1. Electric charges and fields
Let \(\sigma\) be the uniform surface charge density of two infinite thin plane sheets shown in figure. Then the electric fields in three different region \(E_{ I }, E_{ II }\) and \(E_{III}\) are
- A \(\vec{E}_{ I }=\frac{2 \sigma}{\epsilon_0} \hat{n}, \vec{E}_{ II }=0, \vec{E}_{ III }=\frac{2 \sigma}{\epsilon_0} \hat{n}\)
- B \(\vec{E}_{ I }=0, \vec{E}_{ II }=\frac{\sigma}{\epsilon_0} \hat{n}, \vec{E}_{ III }=0\)
- C \(\vec{E}_{ I }=\frac{\sigma}{2 \epsilon_0} \hat{n}, \vec{E}_{\text {II }}=0, \vec{E}_{ III }=\frac{\sigma}{2 \epsilon_0} \hat{n}\)
- D \(\vec{E}_{ I }=-\frac{\sigma}{\epsilon_0} \hat{n}, \vec{E}_{\text {II }}=0, \vec{E}_{\text {III }}=\frac{\sigma}{\epsilon_0} \hat{n}\)
Answer & Solution
Correct Answer
(D) \(\vec{E}_{ I }=-\frac{\sigma}{\epsilon_0} \hat{n}, \vec{E}_{\text {II }}=0, \vec{E}_{\text {III }}=\frac{\sigma}{\epsilon_0} \hat{n}\)
Step-by-step Solution
Detailed explanation
Assuming RHS to be \(\hat{n}\) \(\vec{E}_{ I }=\frac{\sigma}{2 \epsilon_0}(-\hat{n})+\frac{\sigma}{2 \epsilon_0}(-\hat{n})=-\frac{\sigma}{\epsilon_0} \hat{n}\) \(\vec{E}_{I I}=0\),…
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