JEE Mains · Maths · STD 12 - 11. three dimension geometry
The shortest distance between the lines \(\frac{x+2}{1}=\frac{y}{-2}=\frac{z-5}{2}\) and \(\frac{x-4}{1}=\frac{y-1}{2}=\frac{z+3}{0}\) is \(......\).
- A \(6\)
- B \(9\)
- C \(7\)
- D \(8\)
Answer & Solution
Correct Answer
(B) \(9\)
Step-by-step Solution
Detailed explanation
Given lines \(\frac{x+2}{1}=\frac{y}{-2}=\frac{z-5}{2} \& \frac{x-4}{1}=\frac{y-1}{2}=\frac{z+3}{0}\) Formula for shortest distance S.D.…
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