JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
If an air bubble of diameter \(2\) mm rises steadily through a liquid of density \(2000\) kg/m\(^3\) at a rate of \(0.5\) cm/s, then the coefficient of viscosity of liquid is _______ Poise. (Take \(g = 10\) m/s\(^2\))
- A \(0.88\)
- B \(8.8\)
- C \(88.8\)
- D \(0.088\)
Answer & Solution
Correct Answer
(B) \(8.8\)
Step-by-step Solution
Detailed explanation
The terminal velocity of an air bubble rising in a liquid is given by Stokes' law: \(v = \dfrac{2}{9} \dfrac{r^2 \rho g}{\eta}\) Where: \(r = \dfrac{D}{2} = 1 \text{ mm} = 10^{-3} \text{ m}\) \(\rho = 2000 \text{ kg/m}^3\) \(g = 10 \text{ m/s}^2\)…
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