JEE Mains · Maths · STD 11 - 9. straight line
A ray of light coming from the point \((2,2 \sqrt{3})\) is incident at an angle \(30^{\circ}\) on the line \(x=1\) at the point \(A\). The ray gets reflected on the line \(x =1\) and meets \(x\) -axis at the point \(B\). Then, the line \(AB\) passes through the point
- A \(\left(3,-\frac{1}{\sqrt{3}}\right)\)
- B \((3,-\sqrt{3})\)
- C \(\left(4,-\frac{\sqrt{3}}{2}\right)\)
- D \((4,-\sqrt{3})\)
Answer & Solution
Correct Answer
(B) \((3,-\sqrt{3})\)
Step-by-step Solution
Detailed explanation
For point A \(\tan 60^{\circ}=\frac{2 \sqrt{3}- k }{2-1}\) \(\sqrt{3}=2 \sqrt{3}- k\) \(\therefore \quad k=\sqrt{3}\) so point \(A (1, \sqrt{3})\) Now slope of line \(AB\) is \(m _{ AB }=\tan 120^{\circ}\) \(m m _{ AB }=-\sqrt{3}\) Now equation of line \(AB\) is…
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