JEE Mains · Physics · STD 12 - Electric potential and capacitance
- JEE Mains 2021
- Medium
- Numerical
Four identical rectangular plates with length, \(l=2\, cm\) and breadth, \(b =\frac{3}{2}\, cm\) are arranged as shown in figure. The equivalent capacitance between \(A\) and \(C\) is \(\frac{ x \varepsilon_{0}}{ d } .\) The value of \(x\) is (Round off to the Nearest Integer)

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Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\(C _{ eq }=\frac{2 C _{0}}{3}=\frac{2}{3} \frac{ \epsilon _{0} A }{ d }\)
\(C _{ eq }=\frac{2 \epsilon_{0}}{3 d } \times\left(2 \times \frac{3}{2}\right)=2\left(\because A =1 b =2 \times \frac{3}{2}\right)\)981-s594
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