JEE Mains · Physics · STD 12 - 10. Wave optics
An unpolarized light is incident on the plane interface of air-dielectric medium shown in figure. If the incident angle is equal to Brewster angle, identify the expression representing reflected wave.
- A \((E_x\hat{i} + E_y\hat{j})\sin(kx - kz - \omega t)\)
- B \((E_x\hat{i} + E_z\hat{k})\sin(kx + ky - \omega t)\)
- C \((E_x\hat{j} + E_y\hat{k})\sin(ky + kz - \omega t)\)
- D \((E_x\hat{i} + E_y\hat{j} + E_z\hat{k})\sin(kx + ky - kz - \omega t)\)
Answer & Solution
Correct Answer
(A) \((E_x\hat{i} + E_y\hat{j})\sin(kx - kz - \omega t)\)
Step-by-step Solution
Detailed explanation
From the given figure, the incident light rays lie in the \(xz\)-plane. Therefore, the plane of incidence is the \(xz\)-plane. The incident wave travels from the air (\(z 0\)), so it propagates in the \(+x\) and \(+z\) directions. The reflected wave will travel back into the…
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