JEE Mains · Maths · STD 12 - 11. three dimension geometry
The shortest distance between the \(z-\) axis and the line \(x + y + 2z - 3\, = 0 \,= 2x + 3y + 4z - 4\), is
- A \(1\)
- B \(2\)
- C \(4\)
- D \(3\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
Theequation of anyplane passing through given line is \((x+y+2 z-3)+\lambda(2 x+3 y+4 z-4)=0\) \(\Rightarrow(1+2 \lambda) x+(1+3 \lambda) y+(2+4 \lambda) z-(3+4 \lambda)=0\) If this plane is parallel to z-axis then normal to the plane will be perpendicular to z-axis.…
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