JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
An unknown metal of mass \(192\, g\) heated to a temperature of \(100\,^oC\) was immersed into a brass calorimeter of mass \(128\, g\) containing \(240\, g\) of water at a temperature of \(8.4\,^oC\). Calculate the specific heat of the unknown metal if water temperature stabilizes at \(21.5\,^oC\). (Specific heat of brass is \(394\, J\, kg^{-1}\, K^{-1}\)) ......... \(J\, kg^{-1}\, K^{-1}\)
- A \(458\)
- B \(920\)
- C \(1232\)
- D \(654\)
Answer & Solution
Correct Answer
(B) \(920\)
Step-by-step Solution
Detailed explanation
\(Heat\,loss = Heat\,gain\) \(192 \times S\left( {100 - 21.5} \right)\) \( = \left( {128 \times 0.394 + 240 \times 4.2} \right)\left( {21.5 - 8.4} \right)\) \(192 \times 78.5 \times S = 1058.432 \times 13.1\) \(S = 0.91995\,J/g\,{K^{ - 1}}\) \(S = 919.95\,J/kg\,{K^{ - 1}}\)
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