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JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
  • JEE Mains 2019
  • Medium
  • Numerical

An unknown metal of mass \(192\, g\) heated to a temperature of \(100\,^oC\) was immersed into a brass calorimeter of mass \(128\, g\) containing \(240\, g\) of water at a temperature of \(8.4\,^oC\). Calculate the specific heat of the unknown metal if water temperature stabilizes at \(21.5\,^oC\). (Specific heat of brass is \(394\, J\, kg^{-1}\, K^{-1}\)) ......... \(J\, kg^{-1}\, K^{-1}\)

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Answer & Solution

Correct Answer

(B) \(920\)

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Detailed explanation

\(Heat\,loss = Heat\,gain\)

\(192 \times S\left( {100 - 21.5} \right)\)

\( = \left( {128 \times 0.394 + 240 \times 4.2} \right)\left( {21.5 - 8.4} \right)\)

\(192 \times 78.5 \times S = 1058.432 \times 13.1\)

\(S = 0.91995\,J/g\,{K^{ - 1}}\)

\(S = 919.95\,J/kg\,{K^{ - 1}}\)

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