JEE Mains · Maths · STD 11 - 9. straight line
Let the triangle PQR be the image of the triangle with vertices \((1,3),(3,1)\) and \((2,4)\) in the line \(x+2 y=2\). If the centroid of \(\triangle \mathrm{PQR}\) is the point \((\alpha, \beta)\), then \(15(\alpha-\beta)\) is equal to :
- A \(19\)
- B \(24\)
- C \(21\)
- D \(22\)
Answer & Solution
Correct Answer
(D) \(22\)
Step-by-step Solution
Detailed explanation
The centroid \(G^{\prime \prime}(\alpha, \beta)\) of \(\triangle P Q R\) be image of centroid of given triangle \(P^{\prime} Q^{\prime} R^{\prime}\). Centroid of \(\Delta P^{\prime} Q^{\prime} R^{\prime}=\left(\frac{1+3+2}{3}, \frac{3+1+4}{3}\right)=\)…
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