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JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2025
  • Medium
  • Numerical

An ideal gas has undergone through the cyclic process as shown in the figure. Work done by the gas in the entire cycle is ______ \(\times 10^{-1} \mathrm{~J}\).
(Take \(\pi=3.14\))

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Answer & Solution

Correct Answer

(B) 314

Step-by-step Solution

Detailed explanation


Area of circle, \(\mathrm{W}=\frac{\pi}{4} \mathrm{~d}_1 \mathrm{~d}_2\)
\(\mathrm{W}=\frac{\pi}{4}(500-300) \times 10^3(350-150) \times 10^{-6}\)
W = 31.4 Joule
\(\mathrm{W}=314 \times 10^{-1} \mathrm{Joule}\)
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