JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2025
- Medium
- Numerical
An ideal gas has undergone through the cyclic process as shown in the figure. Work done by the gas in the entire cycle is ______ \(\times 10^{-1} \mathrm{~J}\).
(Take \(\pi=3.14\))

Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) 314
Step-by-step Solution
Detailed explanation

Area of circle, \(\mathrm{W}=\frac{\pi}{4} \mathrm{~d}_1 \mathrm{~d}_2\)
\(\mathrm{W}=\frac{\pi}{4}(500-300) \times 10^3(350-150) \times 10^{-6}\)
W = 31.4 Joule
\(\mathrm{W}=314 \times 10^{-1} \mathrm{Joule}\)
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