JEE Mains · Physics · STD 12 - 3. current electricity
An ideal cell of emf \(10\, V\) is connected in circuit shown in figure. Each resistance is \(2\, \Omega .\) The potential difference (in \(V\)) across the capacitor when it is fully charged is

- A \(8\)
- B \(10\)
- C \(15\)
- D \(25\)
Answer & Solution
Correct Answer
(A) \(8\)
Step-by-step Solution
Detailed explanation
\(R _{1}\) to \(R _{5} \rightarrow\) each \(2 \Omega\) Cap. is fully charged So no current is there in branch \(ADB\) Effective circuit of current flow \(R_{e q}=\left(\frac{4 \times 2}{4+2}\right)+2\) \(R _{ eq }=\frac{4}{3}+2=\frac{10}{3} \Omega\) \(i=\frac{10}{10 / 3}=3 A\)…
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