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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2022
  • Medium
  • Numerical

A \(110 \; V , 50 \; Hz , AC\) source is connected in the circuit (as shown in figure). The current through the resistance \(55 \; \Omega\), at resonance in the circuit, will be \(\dots \; A\).

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Answer & Solution

Correct Answer

(A) \(0\)

Step-by-step Solution

Detailed explanation

At resonance \(I _{ L }= I _{ C }\)

Alternatively,

\(\frac{1}{Z}=\sqrt{\left(\frac{1}{X_{L}}-\frac{1}{X_{C}}\right)^{2}}\)

At resonance, \(X _{ L }= X _{ C }\) and \(Z \rightarrow \infty\)

\(\therefore Z_{\text {total circuit }} \rightarrow \infty\) i.e, \(I=0\)

Ans. \(0\)

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