JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A thin circular disc is in the \(xy\) plane as shown in the figure. The ratio of its moment of inertia about \(z\) and \(z'\) axes will be
- A \(1:2\)
- B \(1:4\)
- C \(1:3\)
- D \(1:5\)
Answer & Solution
Correct Answer
(C) \(1:3\)
Step-by-step Solution
Detailed explanation
As we know, moment of inertia of a disc about an axis passing through \(C.G.\) and perpendicular to its plane, \({I_z}\, = \frac{{m{R^2}}}{2}\) Moment of inertia of a disc about a tangential axis perpendicular to its own plane, \({I_z}'\, = \frac{3}{{20}}m{R^2}\)…
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