ExamBro
ExamBro
JEE Mains · Physics · STD 11 - System of particles and rotational motion
  • JEE Mains 2018
  • Hard
  • MCQ

A thin circular disc is in the \(xy\) plane as shown in the figure. The ratio of its moment of inertia about \(z\)  and \(z'\)  axes will be

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(C) \(1:3\)

Step-by-step Solution

Detailed explanation

As we know, moment of inertia of a disc about an axis passing through \(C.G.\)  and perpendicular to its plane, \({I_z}\, = \frac{{m{R^2}}}{2}\) Moment of inertia of a disc about a tangential axis perpendicular to its own plane,

 \({I_z}'\, = \frac{3}{{20}}m{R^2}\)             

\({I_z}/{I_z}'\, = \frac{{m{R^2}}}{2}/\frac{{3m{R^2}}}{2}\, = 1/3\) 

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app