JEE Mains · Maths · STD 11 - 8. sequence and series
Let \(S=\mathbf{N} \cup\{0\}\). Define a relation \(R\) from \(S\) to \(\mathbf{R}\) by :
\(\mathrm{R}=\left\{(x, y): \log _{\mathrm{e}} y=x \log _{\mathrm{e}}\left(\frac{2}{5}\right), x \in \mathrm{~S}, y \in \mathbf{R}\right\}\)
Then, the sum of all the elements in the range of \(R\) is equal to :
- A \(\frac{10}{9}\)
- B \(\frac{3}{2}\)
- C \(\frac{5}{2}\)
- D \(\frac{5}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{5}{3}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & S=\{0,1,2,3 \ldots \ldots\} \\ & \log _y y=\log _e\left(\frac{2}{5}\right) \\ & \Rightarrow y=\left(\frac{2}{5}\right)^x\end{aligned}\) Required Sum…
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