JEE Mains · Physics · STD 11 - 3.2 motion in plane
A stone tied to \(180 cm\) long string at its end is making 28 revolutions in horizontal circle in every minute. The magnitude of acceleration of stone is \(\frac{1936}{ x }\,ms ^{-2}\). The value of \(x.........\left(\text { Take } \pi=\frac{22}{7}\right)\)
- A \(124\)
- B \(123\)
- C \(125\)
- D \(122\)
Answer & Solution
Correct Answer
(C) \(125\)
Step-by-step Solution
Detailed explanation
\(a=\omega^2 R=\left(\frac{28 \times 2 \pi}{60}\right)^2 \times 1.8\) \(=\left(\frac{56}{60} \times \frac{22}{7}\right)^2 \times 1.8\) \(=\frac{(44)^2}{225} \times 1.8\) \(=\frac{1936 \times 1.8}{225}\) \(x=125\)
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