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JEE Mains · Physics · STD 11 - Motion in plane
  • JEE Mains 2023
  • Easy
  • Numerical

A stone tied to \(180 cm\) long string at its end is making 28 revolutions in horizontal circle in every minute. The magnitude of acceleration of stone is \(\frac{1936}{ x }\,ms ^{-2}\). The value of \(x.........\left(\text { Take } \pi=\frac{22}{7}\right)\)

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Answer & Solution

Correct Answer

(C) \(125\)

Step-by-step Solution

Detailed explanation

\(a=\omega^2 R=\left(\frac{28 \times 2 \pi}{60}\right)^2 \times 1.8\)

\(=\left(\frac{56}{60} \times \frac{22}{7}\right)^2 \times 1.8\)

\(=\frac{(44)^2}{225} \times 1.8\)

\(=\frac{1936 \times 1.8}{225}\)

\(x=125\)

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