JEE Mains · Physics · STD 11 - Fluid mechanics
- JEE Mains 2014
- Medium
- MCQ
The velocity of water in a river is \(18\, km/h\) near the surface. If the river is \(5\, m\) deep, find the shearing stress between the horizontal layers of water. The co-efficient of viscosity of water \(= 10^{-2}\,,poise\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(10^{-2}\,N/m^2\)
Step-by-step Solution
Detailed explanation
\(\eta = {10^{ - 2}}poise\)
\(v = 18\,km/h = \frac{{18000}}{{3600}} = 5m/s\)
\(l = 5\,m\)
\(Strain\,rate = \frac{v}{l}\)
Coefficient of viscosity,
\(\eta = \frac{{shearing\,stress}}{{strain\,rate}}\)
\(\therefore \,Shearing\,stress = \eta \times strain\,rate\)
\( = {10^{ - 2}} \times \frac{5}{5} = {10^{ - 2}}N{m^{ - 2}}\)
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