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JEE Mains · Physics · STD 11 - Fluid mechanics
  • JEE Mains 2014
  • Medium
  • MCQ

The velocity of water in a river is \(18\, km/h\) near the surface. If the river is \(5\, m\) deep, find the shearing stress between the horizontal layers of water. The co-efficient of viscosity of water \(= 10^{-2}\,,poise\)

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Answer & Solution

Correct Answer

(B) \(10^{-2}\,N/m^2\)

Step-by-step Solution

Detailed explanation

\(\eta  = {10^{ - 2}}poise\)

\(v = 18\,km/h = \frac{{18000}}{{3600}} = 5m/s\)

\(l = 5\,m\)

\(Strain\,rate = \frac{v}{l}\)

Coefficient of viscosity,

\(\eta  = \frac{{shearing\,stress}}{{strain\,rate}}\)

\(\therefore \,Shearing\,stress = \eta  \times strain\,rate\)

\( = {10^{ - 2}} \times \frac{5}{5} = {10^{ - 2}}N{m^{ - 2}}\)

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