JEE Mains · Physics · STD 12 - 3. current electricity
A \(2\, W\) carbon resistor is color coded with green, black, red and brown respectively. The maximum current which can be passed through this resistor is .............. \(mA\)
- A \(20\)
- B \(100\)
- C \(0.4\)
- D \(63\)
Answer & Solution
Correct Answer
(A) \(20\)
Step-by-step Solution
Detailed explanation
By colour coding, \({\mathrm{R}=50 \times 10^{2}\, \Omega} \) \({\mathrm{I}^{2} \mathrm{R}=\mathrm{P}} \) \({\mathrm{I}=\sqrt{\frac{\mathrm{P}}{\mathrm{R}}}=20 \,\mathrm{m} \mathrm{A}}\)
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