JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2019
- Medium
- Numerical
A \(2\, W\) carbon resistor is color coded with green, black, red and brown respectively. The maximum current which can be passed through this resistor is .............. \(mA\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(20\)
Step-by-step Solution
Detailed explanation
By colour coding,
\({\mathrm{R}=50 \times 10^{2}\, \Omega} \)
\({\mathrm{I}^{2} \mathrm{R}=\mathrm{P}} \)
\({\mathrm{I}=\sqrt{\frac{\mathrm{P}}{\mathrm{R}}}=20 \,\mathrm{m} \mathrm{A}}\)
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