JEE Mains · Maths · STD 11 - 7. binomial theoram
The number of ways of getting a sum \(16\) on throwing a dice four times is ....................
- A \(148\)
- B \(465\)
- C \(789\)
- D \(125\)
Answer & Solution
Correct Answer
(D) \(125\)
Step-by-step Solution
Detailed explanation
\( \left(x^1+x^2 \ldots+x^6\right)^4 \) \( x^4 \cdot\left(\frac{1-x^6}{1-x}\right)^4 \) \( x^4 \cdot\left(1-x^6\right)^4 \cdot(1-x)^{-4} \) \( x^4\left[1-4 x^6+6 x^{12} \ldots .\right]\left[(1-x)^{-4}\right] \) \( \left(x^4-4 x^{10}+6 x^{16} \ldots\right)(1-x)^{-4} \)…
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