A solid disc of radius \('a'\) and mass \('m'\) rolls down without slipping on an inclined plane making an angle \(\theta\) with the horizontal. The acceleration of the disc will be \(\frac{2}{ b } g \sin \theta\) where \(b\) is \(........\). (Round off to the Nearest Integer) \(( g =\) acceleration due to gravity) \((\theta=\) angle as shown in figure \()\)

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Answer & Solution

Correct Answer

(C) \(3\)

Step-by-step Solution

Detailed explanation

\(a=\frac{g \sin \theta}{1+\frac{K^2}{R^{2}}}=\frac{g \sin \theta}{1+\frac{1}{2}}=\frac{2}{3} g \sin \theta\)

\(b=3\)

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