ExamBro
ExamBro
JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2021
  • Medium
  • Numerical

A series \(LCR\) circuit of \(R=5\, \Omega, L=20\, {mH}\) and \({C}=0.5 \,\mu \,{F}\) is connected across an \({AC}\) supply of \(250\, V\), having variable frequency. The power dissipated at resonance condition is \(.....\,\times 10^{2}\, {W}\)

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(125\)

Step-by-step Solution

Detailed explanation

\(X_{L}=X_{c}\) (due to resonance)

\(Z=R \text { So } i_{m s}=\frac{V}{Z}=\frac{V}{R}\)

\(\frac{V^{2}}{R}=\frac{250 \times 250}{5}=125 \times 10^{2} \,W\)

Same subject
Explore more questions on app