JEE Mains · Physics · STD 12 - 8. Electromagnetic waves
A light wave is incident normally on a glass slab of refractive index \(1.5\). If \(4\%\) of light gets reflected and the amplitude of the electric field of the incident light is \(30\, V/m\), then the amplitude of the electric field for the wave propagating in the glass medium will be.......\( V/m\)
- A \(30\)
- B \(10\)
- C \(24\)
- D \(6\)
Answer & Solution
Correct Answer
(C) \(24\)
Step-by-step Solution
Detailed explanation
\(I=\frac{1}{2} \varepsilon_{0} E_{0}^{2} C\) ..... \((i)\) \(0.96\, \mathrm{I}=\frac{1}{2} \mathrm{E}_{0}^{2} \mathrm{V}\) ..... \((ii)\) \(\Rightarrow \quad 0.96=\left(\frac{E_{0}^{\prime}}{E_{0}}\right)^{2} \frac{\varepsilon}{\varepsilon_{0}} \frac{V}{C}\)…
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