JEE Mains · Maths · STD 12 - 7.2 definite integral
Let \(f(x)=\left\{\begin{array}{cc}-2, & -2 \leq x \leq 0 \\ x-2, & 0 < x \leq 2\end{array}\right.\) and \(h(x)=f(|x|)+|f(x)|\). Then \(\int_{-2}^2 \mathrm{~h}(\mathrm{x}) \mathrm{dx}\) is equal to :
- A \(2\)
- B \(4\)
- C \(1\)
- D \(6\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(h(x)=\left\{\begin{array}{cc}x-2+2-x=0, & 0 \leq x \leq 2 \\ -x-2+2=-x & -2 \leq x<0\end{array}\right.\)
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