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JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion

A circular disc of mass \(M\) and radius \(R\) is rotating about its axis with angular speed \(\omega_{1}\) If another stationary disc having radius \(\frac{ R }{2}\) and same mass \(M\) is dropped co-axially on to the rotating disc. Gradually both discs attain constant angular speed \(\omega_{2}\). The energy lost in the process is \(p \%\) of the initial energy. Value of \(p\) is

  1. A \(25\)
  2. B \(27\)
  3. C \(20\)
  4. D \(15\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(20\)

Step-by-step Solution

Detailed explanation

Let moment of inertia of bigger disc is \(I =\frac{ MR ^{2}}{2}\) \(\Rightarrow\) \(MOI\) of small disc \(I_{2}=\frac{M\left(\frac{R}{2}\right)^{2}}{2}=\frac{I}{4}\) by angular momentum conservation…
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