A particle of mass \(m\) is moving with speed \(2\, v\) collides with a mass \(2\,m\) moving with speed \(v\) in the same direction. After collision, the first mass is stopped completely while the second one splits into two particles each of mass \(m\), which move at angle \(45^o\) with respect to the original direction. The speed of each of the moving particle will be

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Answer & Solution

Correct Answer

(B) \({2\sqrt 2 }\,v\)

Step-by-step Solution

Detailed explanation

Linear momentum conservation

\(m\) \(2v + 2m v = m \)\( \times \,0 + m\frac{{v'}}{{\sqrt 2 }} \times 2\)

\(v' = 2\sqrt 2 \,v.\)

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