JEE Mains · Physics · STD 12 -6. Electromagnetic induction
A 1 m long metal rod AB completes the circuit as shown in figure. The area of circuit is perpendicular to the magnetic field of 0.10 T . If the resistance of the total circuit is \(2 \Omega\) then the force needed to move the rod towards right with constant speed (v) of \(1.5 m / s\) is _________ N.
- A \( 7.5 \times 10^{-2} \)
- B \( 5.7 \times 10^{-3} \)
- C \( 5.7 \times 10^{-2} \)
- D \( 7.5 \times 10^{-3} \)
Answer & Solution
Correct Answer
(D) \( 7.5 \times 10^{-3} \)
Step-by-step Solution
Detailed explanation
To maintain constant speed \(F _{ ext }= F _{ B }\) \(=\left(\frac{ vB l}{ R }\right) l B\) \(=\frac{ B ^2 l^2 v }{ R }\) \(=\frac{(0.1)^2 \times(1)^2 \times 1.5}{2}\) \(=7.5 \times 10^{-3} N\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- The current gain of a common emitter amplifier is \(69\). If the emitter current is \(7.0\,mA\), collector current is.....\(mA\)JEE Mains 2017 Medium
- Which of the following pair of nuclei are isobars of the element?JEE Mains 2026 Easy
- A transistor is used in an amplifier circuit in common emitter mode. If the base current changes by \(100 \,\mu A\), it brings a change of \(10 \,mA\) in collector current. If the load resistance is \(2 \,k \Omega\) and input resistance is \(1 \,k \Omega\), the value of power gain is \(x \times 10^{4}\). The value of \(x\) is_________JEE Mains 2022 Medium
- In a conductor, if the number of conduction electrons per unit volume is \(8.5 \times 10^{28}\, m^{-3}\) and mean free time is \(25\,fs\) (femto second), its approximate resistivity is \(\left( {{m_e} = 9.1 \times {{10}^{ - 31}}\,kg} \right)\)JEE Mains 2019 Medium
- The reading of the ammeter (A) in steady state in the following circuit (assuming negligible internal resistance of the ammeter) is _________ A.
JEE Mains 2026 Easy - An electric field of \(1000\,V/m\) is applied to an electric dipole at angle of \(45^o\). The value of electric dipole moment is \(10^{-29}\, C.m.\) What is the potential energy of the electric dipole?JEE Mains 2019 Medium
More PYQs from JEE Mains
- Let the position vectors of points \(A\) and \(B\) be \(\hat{ i }+\hat{ j }+\hat{ k }\) and \(2 \hat{ i }+\hat{ j }+3 \hat{ k },\) respectively. A point \(P\) divides the line segment \(AB\) internally in the ratio \(\lambda: 1(\lambda>0) .\) If \(O\) is the origin and \(\overline{ OB } \cdot \overrightarrow{ OP }-3|\overrightarrow{ OA } \times \overrightarrow{ OP }|^{2}=6,\) then \(\lambda\) is equal toJEE Mains 2020 Hard
- A sinusoidal wave of wavelength 7.5 cm travels a distance of 1.2 cm along the x -direction in 0.3 sec. The crest \(P\) is at \(x=0\) at \(t=0 \mathrm{sec}\) and maximum displacement of the wave is 2 cm. Which equation correctly represents this wave ?JEE Mains 2025 Easy
- If \(y = y ( x ), x \in\left(0, \frac{\pi}{2}\right)\) be the solution curve of the differential equation \(\left(\sin ^{2} 2 x\right) \frac{d y}{d x}+\left(8 \sin ^{2} 2 x+2 \sin 4 x\right) y=\)\(2 e ^{-4 x }(2 \sin 2 x +\cos 2 x )\), with \(y \left(\frac{\pi}{4}\right)= e ^{-\pi}\), then \(y \left(\frac{\pi}{6}\right)\) is equal to.JEE Mains 2022 Hard
- When the wavelength of radiation falling on a metal is changed from \(500 \,nm\) to \(200\, nm ,\) the maximum kinetic energy of the photoelectrons becomes three times larger. The work function of the metal is close to\(.....eV\)JEE Mains 2020 Medium
- This question has Statement \(-1\) and Statement \(-2\). Of the four choices given after the Statements, choose the one that best describes the two Statements. Statement \(1\) : Very large size telescopes are reflecting telescopes instead of refracting telescopes. Statement \(2\) : It is easier to provide mechanical support to large size mirrors than large size lenses.JEE Mains 2013 Hard
- \(\lim _{n \rightarrow \infty} \frac{1}{2^{n}}\left(\frac{1}{\sqrt{1-\frac{1}{2^{a}}}}+\frac{1}{\sqrt{1-\frac{2}{2^{n}}}}+\frac{1}{\sqrt{1-\frac{3}{2^{a}}}}+\ldots \ldots+\frac{1}{\sqrt{1-\frac{2^{a}-1}{2^{n}}}}\right)\) is equal toJEE Mains 2022 Hard