JEE Mains · Maths · STD 12 - 8. Application and integration
The area bounded by the curve \(4 y^{2}=x^{2}(4-x)(x-2)\) is equal to ...... .
- A \(\frac{\pi}{8}\)
- B \(\frac{3 \pi}{8}\)
- C \(\frac{3 \pi}{2}\)
- D \(\frac{\pi}{16}\)
Answer & Solution
Correct Answer
(C) \(\frac{3 \pi}{2}\)
Step-by-step Solution
Detailed explanation
\(4 y^{2}=x^{2}(4-x)(x-2)\) \(|y|=\frac{|x|}{2} \sqrt{(4-x)(x-2)}\) \(\Rightarrow y_{1}=\frac{x}{2} \sqrt{(4-x)(x-2)}\) and \(y_{2}=\frac{-x}{2} \sqrt{(4-x)(x-2)}\) \(D : x \in[2,4]\) Required Area…
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