JEE Mains · Maths · STD 11 - Trigonometrical equations
Two vertical poles of heights, \(20\, m\) and \(80\,m\) stand a apart on a horizontal plane. The height (in meters) of the point of intersection of the lines joining the top of each pole to the foot of the other, from his horizontal plane is
- A \(18\)
- B \(12\)
- C \(16\)
- D \(15\)
Answer & Solution
Correct Answer
(C) \(16\)
Step-by-step Solution
Detailed explanation
\(\frac{h}{y}\, = \frac{{20}}{x},\,\frac{h}{{x - y}} = \frac{{80}}{x}\) \(\frac{h}{{20}} = \frac{y}{x},\,\,\frac{{\,h}}{{80}} = \frac{{x - y}}{x}\) \(\frac{h}{{20}} + \frac{h}{{80}} = 1\) \(h\left( {\frac{{100}}{{1600}}} \right) = 1\) \(h = 16\)
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